Question

In step 6 of the citric acid cycle, succinate + FAD → fumarate + FADH2. Which...

In step 6 of the citric acid cycle, succinate + FAD → fumarate + FADH2. Which statements concerning this reaction are true? Refer to the figure shown. (Note that in redox reactions, the molecule that “causes” another to gain or lose electrons is referred to as the agent.) Select all that apply.
This is not an oxidation/reduction reaction; that is, no electrons have moved.
Fumarate is more oxidized than succinate.
FAD is more reduced than FADH2.
FAD is an oxidizing agent in the reaction.
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Answer #1

succinate + FAD → fumarate + FADH2

This is an oxidation-reduction reaction as succinate is oxidized to fumarate and FAD is reduced to FADH2. So, option A is wrong.

Succinate loss its electrons, it means it has more electrons than fumarate. So, Fumarate is more oxidized than succinate. Option B is correct.

FAD accepts electrons and ger reduced to FADH2. So FADH2 is more rescued than FAD. so option C is wrong.

An oxidizing agent is a compound that accepts electrons and gets reduced. In the given reaction FAD accepts electrons and get reduced to FADH2. So, FAD is oxidizing agent. So option D is also correct.

So correct answers are otpion B and D.

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