What is the probability that the first offspring from the cross listed below will be heterozygous for all loci? (type as a decimal and round to 5 decimal places)
aa | Bb | dd | Ee | x | AA | bb | Dd | Ee |
Four types of gametes will be produced by each of the parent.
aaBbddEe will produce aBdE, aBde, abdE, abde.
AAbbDdEe will produce AbDe, AbDE, AbdE, Abde.
In order to obtain a progeny which is heterozygous for all loci, the gametes must interact in the following way, either aBdE X AbDe or aBde X AbDE.
Total 16 progeny/ offspring will be produced out of which only 2 will be heterozygous for all loci.
Hence the chances of having offspring of heterozygous for all loci will be 2/16 or 1/8 or 12.5%.
So the probability is 0.12500.
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