Question

How many different genotypes are found among the progeny of the cross listed below?

AABBDdEe x AaBbddEe

Answer 1

In the given question,there are 4 sets of genes,with two alleles in each set. two heterozygotes in first parent,satisfying the formula 2² =4

First partner can contribute following types of gametes.

1.ABDE

2.ABDe

3.ABdE

4.ABde

There are three heterozygous set of genes of second parent,satisfying the formula 2³=8 gametes

The second parent will contribute following types of gametes

1.ABdE

2.AbdE

3.ABde

4.AbdE

5.aBdE

6.aBde

7.abdE

8.abde

Considering that each set of gene can have these possibilities after cross over.

1.AA,Aa 2.BB,Bb. 3.Dd,dd. 4.EE,Ee,ee

2×2×2×3=24

Therefore a total of 24 different of genotypes can be formed in the progeny.