Question

You have the great fortune to have been given a miniature dragon. These dragons are prolific...

You have the great fortune to have been given a miniature dragon. These dragons are prolific and rapid breeders. Your dragon has magenta scales and green fire breath which are known to be inherited traits and are coded for by two different loci (genes) with two alleles each You don't know what the genotype of your new dragon is and you want to figure it out so you perform a testcross with your friends silver scaled, red fire breathing dragon.

From this test cross you obtain the following genotypes of baby dragons

Magenta scales, green fire - 44 dragons

silver scales, green fire - 59 dragons

magenta scales, red fire - 56 dragons

silver scales, red fire - 41 dragons

a) From the information given which alleles for each gene are dominant and       which are recessive?

b) What was the genotype of your friend’s dragon?

c) What are all of the possible genotypes of your dragon?

d) Test these possibilities against the observations from the testcross using a chi-squared test (Note: you do not have to do a chi-squared for all possible genotypes, but you do have to come up with the correct genotype).

e) What is the genotype of your dragon? Use the evidence from the results of your cross and your chi-squared test to support your claim.

Homework Answers

Answer #1

My dragon = magenta, green = M_G_

Other dragon = silver, red = mmgg

Ratio obtained after test cross -

44/41, 59/41, 56/41, 41/41

1.07, 1.43, 1.36, 1

The ratio is approximately 1:1:1:1. This is obtained when the dominant genotype is heterozygous at both the loci.

Total # progenies = 56 + 59 + 41 + 44 = 200

Expected # = 200/4 = 50

A. mmgg

B. MMGG, MmGG, MMGg, MmGg

C.

Null hypothesis - The genotype of my dragon is MmGg.

Phenotype #observed #expected (O-E)^2/E
Magenta green 44 50 0.72
Silver green 59 50 1.62
Magenta red 56 50 0.72
Silver red 41 50 1.62

Calculated chi square = 0.72 + 0.72 + 1.62 + 1.62 = 4.68

Degrees of freedom = 4 - 1 = 3

p value = 0.9 to 0.95

Null hypthesis accepted.

The genotype is MmGg.

Please rate high.

Know the answer?
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Not the answer you're looking for?
Ask your own homework help question
Similar Questions
2. Hypothetically, brown color in naked mole rats is dominant to white color and pointed teeth...
2. Hypothetically, brown color in naked mole rats is dominant to white color and pointed teeth is dominant to flat teeth. Suppose you ran across a male naked mole rat that was brown with pointed teeth in class and you wanted to find out if he was homozygous or heterozygous by using a testcross. a. What are the possible genotypes of your male naked mole rat? b. What is the genotype and the phenotype of the female you would mate...
In peas yellow is dominant and green is recessive. You have crossed green peas to yellow...
In peas yellow is dominant and green is recessive. You have crossed green peas to yellow peas and obtained all yellow peas. Indicate the genotype of each parent and the genotype of the F1 progeny. You self-cross the F1 and get 115 individuals 32 green. Give the expected outcome for this cross and perform Chi Squared analysis to determine if this is likely a Mendelian trait (be sure to give expected and observed, show your calculations, and indicate your degrees...
Aliens from planet Zed have very similiar mechanisms of inheritance as humans do. You know that...
Aliens from planet Zed have very similiar mechanisms of inheritance as humans do. You know that in these aliens green skin is dominant to orange skin and long eyestalks are dominant to short eyestalks. Sincec these aliens have been on the planet for such a short time you are unable to generate true breeding parental stocks. You have a female alien that has green skin and long eyestalks and you would like to determine what it's genotype is so you...
Simple Dominance with 2 genes A gene in cats causes them to be black (dominant) or...
Simple Dominance with 2 genes A gene in cats causes them to be black (dominant) or brown (recessive). A second gene causes cats to be agouti (have stripes on their hairs) or non-agouti (solid colored hairs). If you did a dihybrid cross between two black haired agouti cats, what fraction of the offspring would be expected to have each phenotype? If a dihybrid black agouti cat mated with a brown cat that was heterozygous for the agouti gene, what fraction...
ADVERTISEMENT
Need Online Homework Help?

Get Answers For Free
Most questions answered within 1 hours.

Ask a Question
ADVERTISEMENT