5. Use the Hardy-Weinberg equation to predict the expected gene frequencies for a population p(freq of the K allele) = 0.7 and q(freq. of the k allele) = 0.3.
Let us suppose, the given locus in question have two allele and that is K and k. Thus, the expected genotypes will be : KK, homozygous for K allele, Kk heterozygous genotype and kk, homozygous for k allele.
Now assuming the population is at Hardy-Weinberg equilibrium (HWE), we could predic the expected frequency of these three genotypes as the allelic frequency for each allele is know (or given) i.e. p(K) = 0.7 and p(k) = 0.3.
So, according to HWE equation the expected genotype frequency for :
1) KK genotype = p(KK) = {p(K)}2 = {p(K) * p(K)} = 0.7 *0.7 = 0.49
2) Kk genotype = p(Kk) = 2 * {p(K) * p(k)} = 2 * {0.7 * 0.3} = 2 * 0.21 = 0.42
and, 3) kk genotype = p(kk) = {p(k)}2 = {p(k) * p(k)} = 0.3 * 0.3 = 0.09
of the total population.
Get Answers For Free
Most questions answered within 1 hours.