Question

Assume that a cross is made between a heterozygous tall pea plant and a homozygous short...

Assume that a cross is made between a heterozygous tall pea plant and a homozygous short pea plant. Fifty offspring are produced with 30 tall and 20 short plants. A genetics student hypothesizes that the data fit a ratio of 1:1 and wants to test the hypothesis by performing a chi-square analysis. Should the hypothesis be accepted or rejected? Why?

A) should be accepted, p value is greater than 0.05

B) should be accepted, p value is smaller than 0.05

C) should be rejected, p value is greater than 0.05

D) should be rejected, p value is smaller than 0.05

Homework Answers

Answer #1

A. The hypothesis should be accepted as the calculated p value is greater than p=0.05 and the deviations that are observed are by chance.

The necessary calculations are given below.

Know the answer?
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Not the answer you're looking for?
Ask your own homework help question
Similar Questions
1. You cross two homozygous parental pea plants. One has purple flowers and is tall, the...
1. You cross two homozygous parental pea plants. One has purple flowers and is tall, the other has white flowers and is short. All of the F1 plants are purple and short. What are the genotypes of the parents and the F1? If you were to cross the F1 generation, what genotypic and phenotypic ratio would you expect to see in the offspring?
Q1) A cross is made between a pea plant homozygous for two recessive mutations (aabb) and...
Q1) A cross is made between a pea plant homozygous for two recessive mutations (aabb) and a wild-type plant (AABB). The F1 progeny are crossed to a doubly mutant plant (aabb) and the following individuals are observed in the progeny. Number           Phenotype 280                  Wild-type 270                  Both mutant phenotypes 220                  Mutant phenotype a only 230                  Mutant phenotype b only Using the hypothesis that these genes are unlinked, what is the value of chi squared for these data? a) 3.6 b) 100 c) 10.4 d) 1.6 Q2)...
Assume that a Chi-square test was conducted to test the goodness of fit to a 9:3:3:1...
Assume that a Chi-square test was conducted to test the goodness of fit to a 9:3:3:1 ratio and a Chi-square value of 7.6 was obtained. Should the hypothesis be accepted or rejected? Why? (df = n – 1 A) should be accepted, p value is greater than 0.05 B) should be accepted, p value is smaller than 0.05 C) should be rejected, p value is greater than 0.05 D) should be rejected, p value is smaller than 0.05
1. Cross a homozygous purple Plant (PP) with a homozygous white plans (PP). This is called...
1. Cross a homozygous purple Plant (PP) with a homozygous white plans (PP). This is called the P1 cross, and it will produce offspring called the F1 generation. You are given that purple color is dominant to white in this species. a) What is the genotype of the purple plant? b) What gametes can the purple plant make? c) What is the genotype of the white plant? d) What gametes can the white plant make? e) Create a Punnett Square...
The F2 generation from a dihybrid cross produced a total of 219 tall plants with purple...
The F2 generation from a dihybrid cross produced a total of 219 tall plants with purple flowers, 72 dwarf plants with purple flowers, 69 tall plants with pink flowers, and 31 dwarf plants with pink flowers. 1: please state your hypothesis and explain how you arrived at this prediction 2: phenotype observe expected Purple, tall Purple, dwarf Pink, tall Pink, dwarf total number of plants in F2 generation 3: What is the chi-square value between the observed and expected offspring...
Which of the following correctly describes this cross? Choose all that apply. Now determine the genotypes...
Which of the following correctly describes this cross? Choose all that apply. Now determine the genotypes of the possible gametes and set up a Punnett square for the cross between two double heterozygotes, as you did before in a previous question (no need to attach that Punnett square). From your Punnett square, determine how many individual kernels have the genotypes and phenotypes shown in the table below. Enter your answers as a number (e.g. 7) not a word (e.g. seven)...
The expression of yellow petals in sunflowers is due to the dominant allele Y. The homozygous...
The expression of yellow petals in sunflowers is due to the dominant allele Y. The homozygous recessive (y) has orange petals. Plant height is controlled by another gene with two alleles, T and t, with Tall (T) being dominant to short (t). Two individuals that are heterozygous for both traits are crossed, the number of offspring of each phenotype is recorded in the table below. 1. The assumption is that these two genes assort independently. To test this, complete a...
Please answer all the questions A species of scarab beetles have red, orange or golden wing...
Please answer all the questions A species of scarab beetles have red, orange or golden wing covers. A cross between a pair of orange beetles gave 3/4 offspring orange and 1/4 golden.  A cross between a red and an orange pair have 1/2 red and 1/2 orange offspring. How do you explain these results?  Choose the best answer.  The trait is controlled …. Select one: a. by three alleles with incomplete dominance b. by three alleles with both dominance, incomplete dominance and recessive...
When I did this problem I got a very small P value and was told it...
When I did this problem I got a very small P value and was told it is wrong, I do not know which other test would be appropriate for this question. Here is a data set containing plant growth measurements of plants grown in solutions of commonly-found chemicals in roadway runoff. Distilled H2O Petro NaCl MgCl NaCl + MgCl 19.93 19.85 19.87 19.91 19.73 19.91 20.06 19.88 19.92 19.77 20.08 19.99 20.04 19.84 19.75 19.99 19.88 20.05 19.98 19.93 19.9...
6. When analyzing survey results from a two way table, the main distinction between a test...
6. When analyzing survey results from a two way table, the main distinction between a test of independence and a test for homogeneity is: A. How the degrees of freedom are calculated B. how the expected counts are calculated C. the number of samples obtained D. the number of rows in the two way table E. the number of columns in the two way table. 7. A controversial issue in the sport of professional soccer is the use of instant...
ADVERTISEMENT
Need Online Homework Help?

Get Answers For Free
Most questions answered within 1 hours.

Ask a Question
ADVERTISEMENT