Question

For a population in Hardy-Weinberg equilibrium, the frequency of individuals with the recessive phenotype was determined to be 0.49. What is the frequency of the dominant allele in this population?

Answer 1

Answer:

In the question it is given that no of recessive phenotypes is 0.49 which means the recessive genotype is also the same because heterozygous or dominant genotypes don't show recessive phenotypes.

So frequency of recessive genotype (q²)= 0.49

Frequency of recessive allele (q)= √0.49=0.7

According to Hardy-weinberg equation p+q=1

So frequency of dominant allele (p)= 1- q = 1 - 0.7 = 0.3

So the frequency of dominant allele in this population is 0.3 .

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