Tay-Sachs is a recessive disorder that causes death in early childhood. Tim McGraw has determined that he is a carrier (and that his wife, Faith Hill, is normal and does not carry the allele). What are the chances in percent they could have a child with Tay-Sachs?
A. 50 B. 25 C. 0 D. 100
Let the normal allele be T and allele causing Tay Sachs condition be t.
The condition is expressed in a recessive condition, which means that only the individuals with "tt" genotype will have the disease.
Given that the man is a carrier, thus his genotype would be Tt. The female is not a carrier, thus her genotype should be TT.
The cross can be shown as:
Tt x TT
T | t | |
T | TT (normal) | Tt (carrier, normal) |
T | TT (normal) | Tt (carrier, normal) |
Thus, we can observe that in the progeny none is tt. Hence, the chance that Tim and Faith will have a child with Tay Sachs condition is zero.
NOTE: For a recessive disease to appear in offspring, both the mating individuals MUST contain at least one affected allele.
The correct choice should be:
(c) 0
(Kindly upvote if the answer helped).
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