Question

If measuring mRNA instead of enzyme activity for ß-galactosidase was conducted, how would the results differ...

If measuring mRNA instead of enzyme activity for ß-galactosidase was conducted, how would the results differ and what would be expected for the flask containing lactose and chloramphenicol?

Homework Answers

Answer #1

Answer. The flask containing lactose will have high amount of beta galactosidase, as lactose will bind to the repressor, RNA polymerase will bind to the promoter as a result transcription and translation of the lac Z, lac Y and lac A genes occur.

Lac Z codes for beta galactosidase, this helps in breaking lactose to glucose and galactosidase.

Cholrampenicol will inhibit binding of ribosomes to the mRNA, thus translation will be halted and no synthesis of lac Z occurs, thus, no beta galactosidase production.

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