Question

A man has hemophilia and his wife is does not. They have a daughter who has hemophilia. Hemophilia is a sex-linked recessive disease. Provide two Punnett squares to prove the genotype of the wife.

Answer 1

Ans.

Result of condition 1:

2 daughter normal (carrier)

   2 son normal

Result of condition 2 :

2 daughter ( 1 carrier, 1 affected )

2 son ( 1 normal, 1 affected )

From the above punnett square, it can be concluded that the affected daughter is found in condition 2, where the female parent is normal ( carrier ).

Therefore, it can be proved that the genotype of the wife is XHXh [normal female (carrier)] .