Question

A population of Hawaiian Drosophila is segregating two alleles, S and T, of the PGI gene. In a sample of 100 flies form this population, 30 were SS, 60 were ST and 10 were TT. Now that you have calculated the Chi-square value, is this population in Hardy-Weinberg proportions? (Chi-square critical value: 1 degree of freedom = 3.84)

Select one:

A. yes

B. no

Answer 1

Given chi square value = 3.84

Degrees of freedom = 3 - 1 = 2

p value = 0.1 to 0.9

Answer is yes.

Chi square test is a goodness of fit test. It is used to determine whether the differences seen between observed and expected data are due to chance or are statistically significant.

If the probability value is less than 5% or 0.05 then the null hypothesis is rejected and in this case the differences between observed and expected data are statistically significant.

But if the the probability value is more than 0.05, then the differences are purely due to chance and the null hypothesis is accepted.

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