26. A cell experiences complete nondisjunction during meiosis I. One of the resulting gametes combines with a normal haploid gamete. The genome of the progeny would be?
A. haploid
B. diploid
C. triploid
D. tetraploid
E. monosomic
F. trisomic
27. A cell experiences complete nondisjunction during meiosis II. The four resulting gametes each combine with a normal haploid gamete. Half of the progeny genomes would be normal and half of the progeny would be?
A. haploid
B. diploid
C. triploid
D. tetraploid
E. monosomic
F. trisomic
Answer 26) C triploid.
when there is found complete nondisjunction during meiosis 1, then all chromosomes are found in daughter cell whereas other daughter cell is empty. When there is found meiosis 2, then and the daughter cell are diploid in nature having 46 chromosome of both maternal and paternal type. Because there is found splitting of centromere during the anaphase to in the meiosis 2. The diploid gamete is produced which when fused with haploid gamete, then there will be produced triploid zygote.
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Answer 27) triploid
when there is found complete nondisjunction in meiosis 2, then and there is found 46 chromosome in this gametes which are from either paternal in nature or maternal in nature. The fusion of such diploid gametes with haploid gametes produce triploid zygote.
the other half gametes are non viable because they don't have any chromosome count.
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