Question

If a person consumed the upper Acceptable Macronutrient Distribution Range (AMDR) limit for protein as part of a diet containing 10500 kilojoules, approximately how many grams of protein would be ingested?

Group of answer choices

41

219

154

63

Answer 1

The person consumed the upper Acceptable Macronutrient Distribution Range (AMDR) limit for protein.

Diet contains 10500 kilojoules of energy.

First converting it to calories.

1 calorie = 4.184 joules

1 joule = 0.239 calorie

10500 kJ = 2509.56 kcal

AMDR for Protein = 10-35 %.

Here upper limit should be taken as given in the question and that is 35%.

1 Gram of protein = 4 kcal of energy

Therefore,

Protein in grams = Energy (in kcal) × Protein % 4 (kcal)

= 2509.56 × 35 % 4

= 2509.56 × 0.35   4

= 219.58

So 219 gram of protein would be ingested.

Thus the correct answer is (c) 219 gram.

NB - If lower limit is calculated then 63 gram of protein has been ingested.

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