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The value of ?G°\' for the conversion of glucose-6-phosphate to fructose-6-phosphate (F6P) is 1.67 kJ/mol. If...

The value of ?G°\' for the conversion of glucose-6-phosphate to fructose-6-phosphate (F6P) is 1.67 kJ/mol. If the concentration of glucose-6-phosphate at equilibrium is 2.45 mM, what is the concentration of fructose-6-phosphate? Assume a temperature of 25.0 °C. The constant R = 8.3145 J/(mol·K)

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Answer #1

G°' = -RT lnKeq
Keq = Concentration of product/ concentration of reactant = concentration of fructose-6-phosphate (F6P)/ concentration of glucose-6-phosphate
G°' = 1.67kJ/mol = 1670J/mol
R = 8.3145
T = 25 degree °C = 298 °K
1.67 = 298 * 8.3145 lnKeq
ln Keq = - 1670 / 298 * 8.3145
= - 1670/2477.7
lnKeq = -0.674
Keq = e-0.674
Keq = 0.5096
0.5096 = Concentration of fructose-6-phosphate (F6P)/ concentration of glucose-6-phosphate = 2.45mM/ concentration of glucose-6-phosphate
Concentration of glucose-6-phosphate = 2.45 / 0.5096 = 4.80mM

Concentration of glucose-6-phosphate = 4.80mM

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