Question

You are provided 1M Tris-Hcl, pH = 9.0, NaCl (MW = 58.44), and Chelex resin “beads”.

How would you prepare 50ml of a 0.9% Sodium Chloride solution?

Answer 1

Answer =

preparation of  50ml of a 0.9% Sodium Chloride solution as follows:

molecular weight of NaCl = 58.44

0.9 % solution means 0.9 gms of solute in 100 ml of distilled water.

0.9 % NaCl menas 0.9 gms of NaCl in ------------------ 100 ml of water.

0.9 gms ------------------------ 100 ml distilled water -------------- 0.9 %

? gms of NaCl ---------------- 50 ml of distilled water ------------ 0.9 %

= 0.9 X 50 /100

= 45/100

= 0.45 gms.

0.45 gms of NaCl --------- 50 ml of distilled water ------------ 0.9 % solution of NaCl

Therefore weigh 0.45 gms of NaCl then dissoved it in small of water, and dilute upto 50 ml of distilled water to make final volume of 50 ml.