Question

T. Miyake and M. Demerec examined proline-requiring mutations in the bacterium Salmonella typhimurium (T. Miyake and...

T. Miyake and M. Demerec examined proline-requiring mutations in the bacterium Salmonella typhimurium (T. Miyake and M. Demerec. 1960. Genetics 45:755–762). On the basis of complementation testing, they found four proline auxotrophs: proA, proB, proC, and proD. To determine whether proA, proB, proC, and proD loci were located close together on the bacterial chromosome, they conducted a transduction experiment. Bacterial strains that were proC+ and had mutations at proA, proB, or proD were used as donors. The donors were infected with bacteriophages, and progeny phages were allowed to infect recipient bacteria with genotype proC?proA+proB+proD+. The recipient bacteria were then plated on a selective medium that allowed only proC+ bacteria to grow. After this, the proC+ transductants were plated on selective media to reveal their genotypes at the other three pro loci. The following results were obtained:

Donor genotype

Transductant genotype

Number

proC+proA?proB+proD+

proC+proA+proB+proD+

2765

proC+proA?proB+proD+

      3

proC+proA+proB?proD+

proC+proA+proB+proD+

1838

proC+proA+proB?proD+

      2

proC+proA+proB+proD?

proC+proA+proB+proD+

1166

proC+proA+proB+proD?

      0

a) Why are there no proC? genotypes among the transductants?

b)Which genotypes represent single transductants and which represent cotransductants?

c)Is there evidence that proA, proB, and proD are located close to proC? Explain your answer.

Homework Answers

Answer #1

a) Among the trunsductants there are no pro C- genotype because the screening was only performed in the presence of proC-

b) proC+proA+proB+proD+ are the genotype of wild type and single transductants are represented by those genotype on the other hand proC+ proA+ proB+ proD+ and proC+ proA+ proB- proD+ are the cotransductants of proC+ proA- and proC+ proB-

c) From the above data it is clear that the proA and pro B are located close to the proC but the pro D is not.

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