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A color-blind man marries a woman with normal vision whose father was color-blind. Remember that color-blindness...

A color-blind man marries a woman with normal vision whose father was color-blind. Remember that color-blindness is an X-linked recessive trait.

A) What is the probability that their first child will be a color-blind daughter?


B) What is the probability that their first son will be color-blind?

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Answer #1

A.

In this cross, man is color blind and the woman is carrier. Woman is carrier because her father is was colorblind.

The probability of the female being colorblind is 50% or 1/2

The probability of their first child being female is 1/2

So the probability of first child being female and color blind is 1/2 x 1/2 = 1/4

B.

The probability of the son being color blind is 1/2

The probability of first child being color blind is 1/2

So the probability of both events happening together is 1/2 x 1/2 = 1/4

So the first child being color blind is 1/4.

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