Coat colour in a population of rodent is caused by a single locus on the X chromosome where white is dominant over black. Assuming this population is in Hardy-Weinberg equilibrium, what is the frequency of females that have patches of both black and white fur given that the frequency of black individuals is 0.3?
a) 0.70
b) 0.50
c) 0.01
d) 0.84
e) 0.42
ANSWER - CORRECT OPTION IS E
as here it is asked about heterozygous condition,
the dominant frequency is 0.3, lets designate it is p
as we know, the total frequency of hardy weinberg principle is 1
and the formula is P(square) +2PQ+Q(square) , where P is frequncy of dominant homozygous and Q is frequncy of recessive homozygous.
as we know, p+q = 1
and p is mentioned as 0.3 , therefore q is 0.7
to find out the frequncy of heterozygous , we have formula, 2pq
therefore, putting the values we get,
2*0.3*0.7 = 0.42
hence, answer is 0.42
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