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A normal woman whose brother was colorblind but their father and mother did not have color-blindness...

A normal woman whose brother was colorblind but their father and mother did not have color-blindness (in this case we are talking about the common red-green X-linked colorblindness)...

A) is herself heterozygous for the gene causing color blindness

B) has a 50% chance of being heterozygous for the gene causing color blindness

C) has a 25% chance of being heterozygous for the gene causing color blindness

D) has a 10% chance of being heterozygous for the gene causing color blindness

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Answer #1

Answer: B) has a 50% chance of being heterozygous for the gene causing color blindness

____________________________________

Explanation:

Father & Mother are did not have colorblindness, but son is colorblind means one of the parents is carrier.

Father is normal and has only one X chromosome, that means Mother is carrier.

Now we will see in the punnet square-

X Y
X XX XY
X XX XY

You can see, chances of son to be colorblind is 50% (1 out of 2)

You can see, chances of daughter to be carrier is 50% (1 out of 2) (answer to this question)

XX is normal daughter, XX is carrier daughter, XY is normal son, XY is colorblind son

XX is colorblind dauther which is not possible in above situation.

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