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Suppose Long-tailed lizards are dominant to short-tailed, and yellow throated lizards are dominant to blue throated...

Suppose Long-tailed lizards are dominant to short-tailed, and yellow throated lizards are dominant to blue throated (I made this up). If lizard 1, a long tail yellow throat lizard mates with lizard 2, a short tail yellow throat lizard, and the following phenotypic ratios are observed:

11 lizards are long and yellow

3 lizards are long and blue

14 lizards are short and yellow

5 lizards are short and blue

1) Using these genotypes AaBb x aaBb what is the chi-square value associated with the observed offspring? (2 points)

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Answer #1

Null hypothesis - genotype of parents is AaBb and aaBb.

AaBb × aaBb

Gametes aB ab
AB AaBB AaBb
Ab AaBb Aabb
aB aaBB aaBb
ab aaBb aabb

Expected phenotypic ratio = 3 : 1 : 3 : 1

3 (long yellow), 1 (long blue), 3 (short yellow), 1 (short blue)

Total # progenies = 11 + 14 + 5 + 3 = 33

Phenotypes #observed #expected (O-E)^2/E
Long yellow 11 3/33 × 100 = 9.09 0.401
Long blue 3 3.03 0.00029
Short yellow 14 9.09 2.65
Short blue 5 3.03 1.28

Calculated chi square value = 0.401 + 0.00029 + 2.65 + 1.28 = 4.33129

Degrees of freedom = 4 - 1 = 3

P value = 0.1 to 0.9

Null hypothesis accepted.

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