Suppose Long-tailed lizards are dominant to short-tailed, and yellow throated lizards are dominant to blue throated (I made this up). If lizard 1, a long tail yellow throat lizard mates with lizard 2, a short tail yellow throat lizard, and the following phenotypic ratios are observed:
11 lizards are long and yellow
3 lizards are long and blue
14 lizards are short and yellow
5 lizards are short and blue
1) Using these genotypes AaBb x aaBb what is the chi-square value associated with the observed offspring? (2 points)
Null hypothesis - genotype of parents is AaBb and aaBb.
AaBb × aaBb
Gametes | aB | ab |
AB | AaBB | AaBb |
Ab | AaBb | Aabb |
aB | aaBB | aaBb |
ab | aaBb | aabb |
Expected phenotypic ratio = 3 : 1 : 3 : 1
3 (long yellow), 1 (long blue), 3 (short yellow), 1 (short blue)
Total # progenies = 11 + 14 + 5 + 3 = 33
Phenotypes | #observed | #expected | (O-E)^2/E |
Long yellow | 11 | 3/33 × 100 = 9.09 | 0.401 |
Long blue | 3 | 3.03 | 0.00029 |
Short yellow | 14 | 9.09 | 2.65 |
Short blue | 5 | 3.03 | 1.28 |
Calculated chi square value = 0.401 + 0.00029 + 2.65 + 1.28 = 4.33129
Degrees of freedom = 4 - 1 = 3
P value = 0.1 to 0.9
Null hypothesis accepted.
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