Question

A normal blood glucose level in dogs is 3.3 - 6.1 mmol/L. This dog shows a blood glucose level of 1.6 mmol/L and is depressed, ataxic, and disoriented. Treatment of acute hypoglycemia consists of an IV bolus of 1 - 2 mL/kg of 50% dextrose (D-glucose) via central venous line or 2 - 4 mL/kg of 25% dextrose via peripheral vein over three minutes.

-How would you make 50 mL of 25% dextrose from a sterile 50% dextrose solution and sterile water?

-What is the volume of the bolus for peripheral vein administration?

- How much dextrose does the bolus contain?

-The formula weight of anhydrous dextrose is 180.1559 g. What is the molarity of 25% dextrose solution?

-How many mmoles of dextrose are you administering?

-What is the molarity of glucose in the blood at normal levels?

Answer 1

1. Add 25 mL of 50% dextrose solution to 25 mL of sterile water

2. 2-4 mL/kg

3. 50% dextrose (D-glucose) via central venous line or 25% dextrose via peripheral vein

25% dextrose solution is 25gm in 100ml

250 gm in 1L

Molecular weight of dextrose is 180.1559g

Molarity is 250/180.1559 = 1.3876 M

5)

1-M solution will have 1 mole of solute dissolved in 1 litre of solution.

Molarity = 1.3876M

Volume = 1mL

Molarity = moles of solute/litre of solution

3876. oles of solute/ 0.001L

moles of solute = 0.0013876/mL in 25% dextrose solution

6)

Normal blood glucose level in dogs is 3.3 - 6.1 mmol/L