Question

a population consists of 1000individuals with the following genotypes:

AA 350

Aa 525

aa 125

what is the frequency of A?

frequency of a?

genotypic frequency of this population?

show calculations.

Answer 1

According to given data in question..

Total no. Dominant in the population = AA +

= 350+525= 875

So the frequency of A allele= 875÷1000

= 0.875

This frequency is equal of p2+2pq, so according to hardy Weinberg principal

p2+2pq+q2=1

0.875 + q2= 1

q2= 1- 0.875

=0.125

q = √0.125

  q = 0.35,

s​o the frequency of Alelle A

p+q=1

p + 0.35 = 1

p = 1- 0.35

p = 0.65

​​​​​​Now the genotupic frequency of all three genotype in the population.........

Genotypic frequency of AA.....

p2 = 0.65 × 0.65

p2= 0.422

Genotypic frequency of aa....

q2= 0.35 × 0.35

q2 = 0.122

genotypic frequency of Aa.......

2pq = 2× 0.65 × 0.35

2pq = 0.455