Question

In this question, you have a set of ten quantitative values for each of three genotypes: aa, Aa, and AA (Table 1 below). Here, A is the risk or increaser allele. We use the genotype codes 0, 1, and 2, corresponding to the number of A alleles in an individual's genotype.

GENOTYPE_CODE GENOTYPE

0 aa

1 Aa

2 AA

Using each genotype code's ten quantitative values, you can compute the means and standard deviations. Given this information, what is the genotype code for an individual who has a quantitative trait value of -2.78?

Table 1. Phenotype and genotype values for 30 individuals (10 for each genotype code).

Individuals	Gene Code 0	Gene Code 1	Gene Code 2
1	-4.07	0.718	3.91
2	-4.87	0.839	3.1
3	-5.17	0.163	4.79
4	-5.32	1.58	2.89
5	-0.981	0.0625	4.66
6	-1.7	-0.0541	5.15
7	-4.37	-0.475	3.68
8	-3.17	0.0798	4.14
9	-3.24	-0.0268	1.56
10	-3.59	1.07	4.27
Total	-36.481	3.9554	38.15
Avg	-3.6481	0.39554	3.815

A. 1 or 0 (equally probable).

B. 2.

C. 0.

D. The genotype code cannot be determined from the information.

E. 1.

Answer 1

As you can see from the computed values of mean for each of the gene code, the gene code 0 has the negative value and the other two gene codes have the positive values. The standard deviation for the gene code 0 is calculated and found out to be equal to 1.75 with a mean value of -3.6481 and hence the trait who has a quantitative trait value of -2.78 will be given the code 0.

Hence the answer to the question is : C. 0

Because the mean of the gene code 2 and gene code 1 is positive and also no negative values are there which are beyond -1 in gene code 1, the standard deviation cant be greater than 1 in gene code 1 and hence the gene code 1 wont include the -2.48 trait

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