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1) A woman with blood type A marries a man with blood type B. Their three...

1) A woman with blood type A marries a man with blood type B. Their three children have blood types A, AB, and B. Which trait, if any, is dominant? Explain. What are the genotypes of the parents? What is the probability of these parents having a child with blood type O? Show your Punnett square.

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Answer #1

A and B blood groups are dominant,The alleles I(A) and I(B) both are dominant over allele i as I(A) and I(B) form antigens A and B ,respectively,but i doesn't form any antigen.AB blood group is co-dominance,Both the alleles I(A) and I(B) are co-dominant as both of them are able to express themselves in the presence of each other in blood group AB(I(A)I(B)) by forming antigens A and B.

The genotype of parents is I(A)i,I(B)i.both the parents is having heterozygous allele.

Probability of this parents having child with blood type O is 25%.there is possibility of having 4 types of blood group that is A,B,O,AB.so,probability is 1/4 for each type.for O type it is also same thait 1/4 or 25%.

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