Question

What percentage of ATP energy is produced when 2 moles of glucose react in glycolysis? (7.3 kcal/mole ATP)

What percentage of ATP energy is produced when 2 moles of glucose are oxidized into acetyl CoA? (7.3 kcal/mole ATP) Express your answer to two significant figures.

What percentage of ATP energy is produced when 2 moles of glucose react in the citric acid cycle? (7.3 kcal/mole ATP)

What percentage of ATP energy is produced when 2 moles of glucose are completely oxidized to CO2 and H2O? (7.3 kcal/mole ATP)

Answer 1

Assume 1 NADH = 3ATP; 1 FADH = 2ATP

A. In glycolysis 1 mol of glucose gives 8 ATP
So 2mol gives 16mol ATP
1 mole of glucose is 686 kcal

Kcal in ATP = 7.3 kcal/mol x 16 mol = 116 kcal
% = 116 / 686 X 100 = 17%

B. 1 mol to Glucose to acetyl COA = 14 ATP
So 2mol gives 28 mol ATP
1 mole of glucose is 686 kcal

Kcal in ATP = 7.3 kcal/mol x 28 mol = 204.4 kcal
% = 204 / 686 X 100 = 29.79%

C. 1 mol of Glucose in citric acid cycle = 24 ATP
So 2mol gives 48 mol ATP
1 mole of glucose is 686 kcal

Kcal in ATP = 7.3 kcal/mol x 48 mol = 350.4 kcal
% = 350 / 686 X 100 = 51.07%

D. 1 mol of Glucose = 36 ATP
So 2mol gives 72 mol ATP
1 mole of glucose is 686 kcal

Kcal in ATP = 7.3 kcal/mol x 72 mol = 525.6 kcal
% = 525.6 / 686 X 100 = 76.6%