Question

16. The maternal copy of chromosome 19 has undergone an inversion such that its new ordering...

16. The maternal copy of chromosome 19 has undergone an inversion such that its new ordering is as follows:

A-*-B-E-D-C-F(* denotes the centromere).

The normal ordering of the paternal copy is as follows:

a-*-b-c-d-e-f.

According to the location of the affect chromosome region with respect to the centromere, how would this inversion be classified?

17. Assume the crossing over occurs between d and e during meiosis. Denote all possible monads in the gametes using the asterisk and upper and lower-case letters as above.

18. Gametes containing which of the above monads would NOT be expected to be viable?

Homework Answers

Answer #1
  1. A paracentric ("away from the center") inversion does not include the centromere. In above example C and E have inversed and since these are not located near the centromere, this is a example of paracentric inversion.
  2. Suppose there are 2 chromosomes, A-*-B-C-D-E-F and a-*-b-c-d-e-f. Possible combinations of chromosomes formed during meiosis if 'd' and 'e' crossover are as follows:
  • A-*-B-C-D-E-F, a-*-b-c-d-e-f (normal chromosomes which do not crossover)
  • A-*-B-C-d-e-F ('d' and 'e' from the other chromosome crossover and recombine), a-*-b-c-D-E-f ('D' and 'E' from the other chromosome crossover and recombine).

3. Non-viability is only when a important gene which is essential for survival (ex. House-keeping genes) is missing. Since in the above crossover deletion of any gene is not occuring and hence, all the monads will be viable.

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