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Widow’s Peak is dominant to not having it. A woman who has widow’s peack marries a...

Widow’s Peak is dominant to not having it. A woman who has widow’s peack marries a man who doesn’t. Their first child has his father's phenotype. What are the chances that their second child will have widow’s peak and be a girl?

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Answer #1

Answer:

1/8

Explanation:

Widow's peak = W

Without widow's peak = w

Woman with widow's peak (Ww) x Man without widow's peak (ww)----Paretns

w
W Ww (widow's peak)-1/2
w ww (without widow's peak)-1/2

The probability of girl or boy = 1/2

The first child has his father's phenotype and the chances that their second child will have widow’s peak and be a girl = (first child without widow's peak) * (second child with widow's peak) * (probability of girl) = 1/2 * 1/2 * 1/2 = 1/8

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