Question

Hair curl in humans is controlled by a single gene. There are two alleles. HC codes...

Hair curl in humans is controlled by a single gene. There are two alleles. HC codes for curly hair. HS codes for straight hair. There is incomplete dominance between the alleles. A person with curly hair has a child with a person who has straight hair.

A. What is the genotype of the parent with straight hair?

B. What is the genotype of the parent with curly hair?

C. What is the genotype of their child?

D. What is the phenotype of their child?

E. If two people with wavy hair have a child, what is the probability that their first child will have wavy hair?

Monohybrid Cross with Co-Dominance

4. Pretend that humans have one gene that controls their choice of favorite snacks. Allele ST encodes a preference for salty snacks while allele SW encodes a preference for sweet snacks. There is codominance between the alleles. A person who only likes salty snacks has a child with someone who only likes sweet snacks.

A. What is the genotype of the parent who only likes salty snacks?

B. What is the genotype of the parent who only likes sweet snacks?

C. What is the genotype of their child?

D. What is the phenotype of their child?

Thank you for your help. When you complete the Gamete table, Please use upper and lower case levels. I would like to make sure the answer I have is correct. Thank you

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Answer #1

hair type gene shows incomplete dominance, those who have curly hair and straight hair are homozygotes and those who have wavy hair are heterozygotes.

A) HSHS

B) HCHC

C) HSHS * HCHC

HS HS
HC HSHC ( wavy hair) HSHC ( wavy hair)
HC HSHC ( wavy hair) HSHC ( wavy hair)

the genotype of their child is HSHC.

D) The phenotype of their child is wavy hair.

E) HSHC * HSHC

HS HC
HS HSHS ( straight hair) HSHC ( wavy hair)
HC HSHC ( wavy hair) HCHC ( curly hair)

probability of getting child with wavy hair= number of children with wavy hair/total number of progeny

=2/4

= 1/2

If two people with wavy hair have a child, the probability that their first child will have wavy hair = 1/2.

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