Question

**Please answer neatly and please remember this is grade
12 biology!! Thank you**

The average length of a nucleotide is 0.34 X 10 ^{-9} m
and there are 6 X 10^{9} base pairs in a human diploid
cell. If there are approximately 5.0 X 10^{13} cells in a
mature human and the distance to the sun is approximately 1.5 X
10^{11} m, determine how many times the DNA from one human
could reach the sun and return. Show the math for full marks.

Answer #1

The average length of a nucleotide = 0.34 X 10-9 m

No. of base pairs in a human diploid cell = 6 X 109

Total number of cells in a mature human = 5.0 X 1013 (approx.)

Distance that can be covered if the DNA from all cells is opened up from end to end = (0.34 X 10-9) X (6 X 109) X (5.0 X 1013) = 1.7 X 1013 m.

Distance between the sun and earth = 1.5 X 1011

Since we have to travel back the actual distance = 2 X 1.5 X 1011 = 3 X 1011

Therefore, the required number of times the DNA from one human could reach the sun and return = (1.7 X 1013 ) / (3 X 1011) = 56.67

Since, the question has asked for the number of times we can
reach the sun and return, it should be a whole number and the
answer should be just **56** ignoring the decimal
point.

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