Question

Freckles are dominant over no freckles. If a woman with freckles (homozygous) reproduces with a man...

Freckles are dominant over no freckles. If a woman with freckles (homozygous) reproduces with a man with no freckles, what are the chances they will have a child with freckles?

Group of answer choices
25%
100%
75




Science   Biology   
0 0
Add a commentTranscribed image text
Next >

Homework Answers

Answer #1

We are told that freckles are dominant over no freckles. Let the freckles are coded by F and no freckles are coded by f.

The female has freckles and is homozygous. Hence, genotypically she sill be FF. The man has no freckles and hence he will be ff.

We are to determine the probability that the child produced by this couple will have freckles. Now freckles can be produced when the child is genotypically FF or Ff. Hence, we are to determine the probability of obtaining either of these genotypes in the offspring.

For this, we perform a cross between the parents using a Punnett square as follows:

F F
f Ff Ff
f Ff Ff

Now, all the organisms here have the same genotype of Ff. Hence, all of the offsprings will have freckles. Therefore, the probability of obtaining offsrping with freckles is 100%.

0 0
Know the answer?
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Log In

Sign Up

Not the answer you're looking for?
Ask your own homework help question
Similar Questions
What is the chance of the offspring of a homozygous dominant man and a heterozygous woman...
What is the chance of the offspring of a homozygous dominant man and a heterozygous woman having a recessive phenotype? a. 25% b. 100% c. 50% d. 75% e. none of the above
9.The allele for freckles is dominant to the allele for no freckles. A freckled man and...
9.The allele for freckles is dominant to the allele for no freckles. A freckled man and a woman without freckles have two children, a boy with freckles and a girl without freckles. Using a Punnett square, determine the genotypes of all four individuals. Mom: X^f X^f Dad: X^f Y
ifba man that is homozygous dominant for unattached earlobes and a woman that us heterzygous for...
ifba man that is homozygous dominant for unattached earlobes and a woman that us heterzygous for unattached earlobes haveba child what is the likelihood of this child having attached ear lobes(%) describe the role of the messenger RNA (mRNA) in protein synthesis. What are homologous chromosomes and what do they have in common? how many homologous pairs do we have in each of our body cells
Critical Thinking: Trait F is the Mendelian trait for freckles, where F is dominant over f....
Critical Thinking: Trait F is the Mendelian trait for freckles, where F is dominant over f. • Timmy is homozygous dominant for trait F. • Timmy mates with Sally who is heterozygous for trait F. • Timmy's father and Timmy's mother are both heterozygous for trait F. • Timmy's maternal grandmother (mother's mother) is homozygous recessive for trait F. • Timmy's maternal grandfather (mother's father) is homozygous dominant for trait F. Use the information provided to complete the three separate...
Sickle cell anemia is an autosomal recessive disease. A man and a woman are both heterozygous...
Sickle cell anemia is an autosomal recessive disease. A man and a woman are both heterozygous for the mutant gene. They have two children and one has the disease. What are the chances their next child will have the disease? 100% 75% 50% 25%
Widow’s Peak is dominant to not having it. A woman who has widow’s peack marries a...
Widow’s Peak is dominant to not having it. A woman who has widow’s peack marries a man who doesn’t. Their first child has his father's phenotype. What are the chances that their second child will have widow’s peak and be a girl?
Using a graph/Punnett square: A woman is heterozygous for polydactyly (which is a dominant condition in...
Using a graph/Punnett square: A woman is heterozygous for polydactyly (which is a dominant condition in which a person has more than the normal number of fingers and/or toes). The woman has a child with a man who is homozygous normal. What is the chance that their child will have more than ten fingers and/or toes?
11. Tim and Christine have freckles (a dominant trait that is not sex linked), but their...
11. Tim and Christine have freckles (a dominant trait that is not sex linked), but their son Michael does not. Use a Punnett square to show how this situation is possible. What is the probability that their next child will have freckles?
Assume that a man with hemophilia marries a phenotypically normal woman whose father had hemophilia. What...
Assume that a man with hemophilia marries a phenotypically normal woman whose father had hemophilia. What is the probability that their first child will have hemophilia? Select one: a. 25% b. 0% c. 75% d. 50% e. 100%
Having freckles is a dominant trait. A person is heterozygous for having freckles. Their genotype is...
Having freckles is a dominant trait. A person is heterozygous for having freckles. Their genotype is _________ and their phenotype is _________. [ Choose the choice with the answers in the correct order. ] * Freckles, Ff ff, freckles freckles, no freckles Ff, Freckles A fertilized egg created through sexual reproduction ______________. * is genetically identical to the parents contains genetic material from only one parent is genetically identical to other eggs of the same parents has a combination of...
ADVERTISEMENT
Need Online Homework Help?

Get Answers For Free
Most questions answered within 1 hours.

Ask a Question
ADVERTISEMENT