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The frequency of allele a is 0.4 for a population in Hardy-Weiberg equilibrium. What is the...

The frequency of allele a is 0.4 for a population in Hardy-Weiberg equilibrium. What is the expected frequency of genotype Aa?

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Answer #1

This is a population in Hardy-Weiberg equilibrium,

In this problem the recessive genotype is represented by (aa) and dominant genotype as (AA).

Given

The frequency of the allele “a” is represented by “q” is 0.4

So the frequency of the allele “A” is represented by “p” where p+q=1; p+0.4=1

So “p”= 0.6

The frequency of genotype is represented by “AA”, “aa”, “Aa”.

The frequency of genotype, “AA”=p=

The frequency of genotype, “aa”=q=

The frequency of genotype, “Aa”= 2pq=

The expected genotypic frequency is

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