Question

Use a Chi square test to determine if the observed numbers 308, 134 and 155 represents...

Use a Chi square test to determine if the observed numbers 308, 134 and 155 represents a ratio of 9:3:4. What is your Chi square value correct to 2 decimal places?"Use a Chi square test to determine if the observed numbers 308, 134 and 155 represents a ratio of 9:3:4. What is your Chi square value correct to 2 decimal places?"

Science   Biology   
0 0
Add a commentTranscribed image text
Next >

Homework Answers

Answer #1

Expected values are calculated by 597/16 x 9= 336, 597/16 x 3= 112, 597 / 16 x 4 = 149

The Chi-square value is 6. 89. But the P value using the tables for the df of 2 is 5.99.

Since the P value is less than the actual Chi-Square value, we consider the difference in the values to be significant and hence the observed numbers 308, 134, and 155 do not represent the ration 9:3:4.

0 0
Know the answer?
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Log In

Sign Up

Not the answer you're looking for?
Ask your own homework help question
Similar Questions
1. The sample data for Chi-square test are called ______ ? a. Expected frequencies b. Observed...
1. The sample data for Chi-square test are called ______ ? a. Expected frequencies b. Observed frequencies c. Expected proportions d. Observed proportions 2. The chi-Square test statistic should not be used if _______? a. fe > 5 for any cell b. fe < 5 for any cell c. fe = fo d. None of the above 3. A nation-wide data indicated that 60% of students approved of the instructors grading policy, 30% disapproved and 10% had no opinion. The...
Consider the observed frequency distribution for the accompanying set of random variables. Perform a​ chi-square test...
Consider the observed frequency distribution for the accompanying set of random variables. Perform a​ chi-square test using α = 0.05 to determine if the observed frequencies follow the Poisson probability distribution when lambda λ=1.5. Random Variable, x Frequency, fo    0    18 1 35 2 30 3 14 4 and more    3 Total    100 What is the null​ hypothesis, H0​? A. The random variable follows a normal distribution. B. The random variable does not follow the Poisson...
You are conducting a multinomial Chi-Square Goodness of Fit hypothesis test for the claim that the...
You are conducting a multinomial Chi-Square Goodness of Fit hypothesis test for the claim that the 4 categories occur with the following frequencies: HoHo : pA=0.1; pB=0.5; pC=0.1;  pD=0.3 Complete the table. Report all answers accurate to three decimal places. Category Observed Frequency Expected Frequency A 17 B 25 C 6 D 16 What is the chi-square test-statistic for this data? χ2= What is the P-Value? P-Value =
In performing a chi-square goodness-of-fit test with multinomial probabilities, the ___________ the difference between observed and...
In performing a chi-square goodness-of-fit test with multinomial probabilities, the ___________ the difference between observed and expected frequencies, the higher the probability of concluding that the probabilities specified in the null hypothesis are correct. larger smaller
If the chi-square test is used to test categorical variables, what are those numbers in the...
If the chi-square test is used to test categorical variables, what are those numbers in the contingency table? What do they represent? How are they calculated?
Review the following output from a chi-square test, and answer the questions below. Chi-Square Test Frequencies:Preference...
Review the following output from a chi-square test, and answer the questions below. Chi-Square Test Frequencies:Preference Observed N Expected N Residual Nuts & Grits 9 20.0 -11.0 Bacon Surprise 27 20.0 7.0 Dimples 16 20.0 -4.0 Froggy 17 20.0 -3.0 Chocolate Delight 31 20.0 11.0 Total 100 Test Statistics Preference Chi-Square 15.800a df 4 Asymp. Sig. .003 a 0 cells (0.0%) have expected frequencies less than 5. The minimum expected cell frequency is 20.0. Answer the following questions about this...
Chi-Square Test for Independence Using Chi-Square, we are looking to see if there is a significant...
Chi-Square Test for Independence Using Chi-Square, we are looking to see if there is a significant difference between what we would expect results to be, and what the actual results were. That is, expected vs. observed.   Use alpha = .05 Listed below are data from a survey conducted recently where Males and Females responded to their happiness with their supervisor (this is fictitious data). Response Male Female Total Not at all 23 25 48 Somewhat 13 22 35 Very 26...
One common application for the chi-square test is a genetic cross. In this case, the statistical...
One common application for the chi-square test is a genetic cross. In this case, the statistical null hypothesis is that the observed results from the cross are the same as those expected, for example, the 3:1 ratio or 1:2:1 ratio for a Mendelian trait. Dr. William Cresko, a researcher at the University of Oregon, conducted several crosses between marine stickleback fish and freshwater stickleback fish. All marine stickleback fish have spines that protrude from the pelvis, which presumably serve as...
Assume that a Chi-square test was conducted to test the goodness of fit to a 9:3:3:1...
Assume that a Chi-square test was conducted to test the goodness of fit to a 9:3:3:1 ratio and a Chi-square value of 7.6 was obtained. Should the hypothesis be accepted or rejected? Why? (df = n – 1 A) should be accepted, p value is greater than 0.05 B) should be accepted, p value is smaller than 0.05 C) should be rejected, p value is greater than 0.05 D) should be rejected, p value is smaller than 0.05
2. Use the Chi-Square test procedure to solve the following research question: A psychologist seeks to...
2. Use the Chi-Square test procedure to solve the following research question: A psychologist seeks to examine whether certain mental health issues are more prevalent in a sample of violent criminal offenders (1,000) compared to the average population. Observed Expected Anxiety disorder 152 146 (14.6 x 1000) Mood disorder 112 80 (8.0 x 1000) Personality disorder 195 90 (9.0 x 1000) Schizophrenia 75 15 (1.5 x 1000) None 521 669 (66.9 x 1000) 2a. Calculate and provide the chi-square statistic...
ADVERTISEMENT
Need Online Homework Help?

Get Answers For Free
Most questions answered within 1 hours.

Ask a Question
ADVERTISEMENT