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If AaBbCcDd is mated to AaBbCcDd (no gene interactions among all genes), what is the probability...

If AaBbCcDd is mated to AaBbCcDd (no gene interactions among all genes), what is the probability that the offspring will have either the phenotype AaB_CcDD or the genotype AAbbCcD_?

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Answer #1

AaB_CcDD have 2 forms AaBbCcDD and AaBBCcDD. We have to find probability of both.

Similarly for, AAbbCcDD or AAbbCcDd for 2nd genotype.

We can find probability by multiplying probabilities of finding required genotype at that loci by same for other loci.

For AaB_CcDD , probability will be =>1/2*3/4*1/2*1/4 = 3/64

For AAbbCcD_, probability will be => 1/4*1/4*1/2*3/4 =3/128.

HINT- For getting Aa probability in AaBbCcD_ , see the probability of getting Aa from the A loci of the 2 parent genotypes. And do same for other loci also and then multiply like I did.

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