Albinism is a recessive disorder that occurs in humans and in guinea pigs too. Assume that an albino guinea pig crossed with a black guinea pig and produces 6 black offspring. When the albino is crossed with a second black guinea pig, 4 black and 3 albino offspring were produced. What genetic explanation would apply to these data?
a. The first black guinea pig had genotype AA and the second one aa
b. The first black guinea pig had genotype Aa and the second one AA
c. The first black guinea pig had genotype aa and the second one Aa
d. The first black guinea pig had genotype Aa and the second one aa
e. The first black guinea pig had genotype AA and the second one Aa
The corect option, which satisfies the genetic explanation is -
Option e -
The first black guinea pig had genotype AA and the second one Aa.
Black is a dominant phenotype than albino., hence the first cross would be between - BB * bb ( albino )
The cross gives rise to all black phenotype with gentoype Bb
When individuals with this phenotype - Bb which is referred to in the question as second black pig is crossed with albino, both black and albino individuals arise.
Hence option E is the perfect one for this question.
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