The following two genotypes are crossed: Aa Bb Cc dd Ee × Aa bb Cc Dd Ee. The proportion of the offspring that are expected to be aa bb Cc Dd Ee assuming Mendelian inheritance is ___.
Answer is 1/64.
Let P1: Aa Bb Cc dd Ee and
P2: Aa bb Cc Dd Ee
The total number of gene pairs that can be formed by taking one gene from every pair = 210
This number includes repeating genotypes.
Now aa bb Cc Dd Ee can be formed by -
a from P1 and a from P2 (only 1 choice)
b from P1 and b from P2 (2 choices as there are 2 b in P2)
(C from P1 and c from P2 ) or ( c from P1 and C from P2)
d from P1 and D from P2 ( 2 choices as P1 has 2 d)
(E from P1 and e from P2) or (e from P1 and E from P2)
Therefore total number of choices to form it = 1×2×2×2×2 = 24
Hence, proportion =
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