Question

The MN blood group is a blood type controlled by a single gene with two loci....

The MN blood group is a blood type controlled by a single gene with two loci. Individuals may be type M (homozygous for the M allele), N
(homozygous for the N allele or MN (heterozygous). In a population of 50 having the blood antigen M, 15 having blood antigen MN and 35 having the blood antigen N. Calculate the frequency of the M allele and the frequency of the N allele of this population.(Show working)

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Answer #1

Applying to the hardy weinberg equilibrium

The frequency of the two alleles (M and N) remians constant and the genotype of the individual follow the frequencies given by

p2 +2pq +q2 = 1

Frequency of the homozygous genotype MM = P2

Frequency of the heterozygous genotype MN = 2pq

Frequency of the homozygous genotype NN= Q2

Gene pool = blood antigen M +blood antigen MN + blood antigen N = 50+15+35 = 100

Genotype frequency of MM = 50/100 = 0.5 = P2

Genotype frequency of MN = 15/100 =0.15 = 2pq , thus pq = 0.15/2 =0.075

Genotype frequncy of NN = 35/100 =0.35 = Q2

Thus ,allele frequency of the M = 0.5 + 0.075 = 0.57

Allele frequency of the N = 0.35 + 0.075 = 0.42

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