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A fish of genotype a/a; B/b is crossed to a fish whose genotype is A/a; B/b....

A fish of genotype a/a; B/b is crossed to a fish whose genotype is A/a; B/b. What proportion of the progeny will be heterozygous for at least one of the genes? (Assume independent assortment.) The answer is 6/8 can someone please show me in detail how to get this fraction from a dihybrid cross?

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Answer #1

As we see, only in the case of aaBB and aabb, the genes are not heterozygous, they ar homozygous i.e. both the alleles for a given gene are of the same type either dominant or recessive.
Since this happens in 4 instances out of 16
We see that in 12 out of 16, or 3/4 cases, the or 75% of the progeny will be heterozygous for at least one of the genes.

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