Question

Determine the molarity of a glucose solution where 180g of glucose (C₆H_`12O₆) is dissolved in 1 liter of water. How many glucose molecules would be present per liter?

Answer 1

When 180g of glucose is dissolved in 1 litre of water, it is 1M

Molarity = moles of solute/ volume of solution(in litres)

molecular weight of glucose = 180g

Mole of a solute is equal to the molecular weight of the solute.

So, for 180 g of glucose which is the molceular weight of glucose,

moles of glucose = 1 mole

So,molarity = 1mole /1 litre

= 1M (ans)

The number of glucose molecules that would be present per litre = Avogadro's number = 6.022*10^23 molecules.