Question

Consider a racoon population that exhibits variation at the G
locus, which has two possible alleles: G_{1} and
G_{2}. The population starts out at Hardy Weinberg
Equilibrium and the frequency of the G_{1} allele in the
original population is 0.3. The relative fitness of each genotype
during this generation is listed below. Use information to answer
the following questions.

*w*_{11} = 0.8

*w*_{12} = 1.0

*w*_{22} = 0.5

Calculate the average fitness for the population.

Calculate the genotype frequencies in the next generation.

Calculate the frequency of the G_{1} allele in the next
generation.

Calculate the frequency of the G_{2} allele in the next
generation.

Calculate the change in the frequency of the G_{1}
allele in the next generation.

Answer #1

the frequency of G1allele is given, p= 0.3,

frequency of G2 allele will be, q= (1-0.3) = 0.7

now average fitness of the population can be calculated as

w= p^{2}w11+2pqw12+q^{2}w22 =
(0.3^{2}x0.8)+(2x0.3x0.7x1)+(0.7^{2}x0.5)=0.737

now genotypic frequency in next generation will be

G1G1 genotype = p^{2} x (W11/avg W) = 0.3^{2}x
(0.8/0.737)= 0.097

G1G2 genotype = 2pq x (W11/avg W) ) = 2x 0.3x 0.7 x (1/0.737) = 0.57

G2G2 genotype = q^{2} x (W11/avg W) = 0.7^{2}x
(0.5/0.737) =0.33

frequency of G1 allele in next genetation = 0.097+( 0.57/2) = 0.382

Frequency of G2 allee in next generation=0.33+( 0.57/2) = 0.615

change in frequency of the G1 allele in next genration = ( 0.382-0.3)/0.3 *100= 27.3%

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P has a frequency of exactly 1% in the population. Given this
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A hypothetical population ofcats has two alleles, TL
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Frequency
2
0.1
3
0.2
5
0.5
7
0.15
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