Agrodiaetus shahrami, a butterfly, has one of the highest chromosome numbers among all multicellular animals (2N=268!). If a butterfly of this species is heterozygous for just 3 genes per chromosome, how many different gametic genotypes are possibly produced by this butterfly?
The haploid set of chromosomes in the butterfly are 134 chromosomes i.e. it has 134 pairs of chromosomes
each chromosome has just 3 genes which are heterozygous rest all are homozygous. Considering a pair of chromosome which is heterozygous for 3 genes, the number of different gene combinations produced during meiosis is 2n, n is the number of genes. Therefore different combination of genes which can be produced from this particular chromosome is 23 = 8.
Every chromosme pair is heterozygous for 3 genes only, so it each pair can produce 8 different combinations of genes. In total there are 134 chromosome pairs, so 134 x 8 = 1072.
1072 different gametic genotypes are possibly produced by the butterfly.
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