Question

Match E1: final electron acceptor in PDH complex Laipote arm: receives electron from lipoate arm in...

Match

E1: final electron acceptor in PDH complex

Laipote arm: receives electron from lipoate arm in PDH complex

NAD+; product of PDH complex

FAD: Leads to decarboxylation of pyruvate in in PDH complex

Acetyl-coa: acetyl-group from E1 to E2 in PDH complex

Homework Answers

Answer #1

E1- leads to decarboxylation of Pyruvate in the PDH complex.

Lipoate arm- acetyl group from E1 to E2 in PDH complex.

NAD+ - final electron acceptor in PDH complex.

FAD- receives electron from lipoate arm in PDH complex.

Acetyl coA- product of PDH complex.

(PDH complex involves decarboxylation of Pyruvate obtained from glycolysis, to yield acetyl coA. Three enzymes are involved in this reaction. E1 (Pyruvate dehydrogenase) is responsible for removing carbon dioxide from Pyruvate, and the acetyl group is transferred to E2, which produces acetyl coA. With the help of E3, electron is transferred from dihydrolipoate to FAD. FADH2​​ produced in this process, donates the electron to the final electron acceptor, NAD+ to generate NADH).

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