Question

What percentage of the offspring will be heterozygous for all six genes?

Aa bb Cc Dd Ee Ff x AA BB Cc DD EE ff

Answer 1

Ans :-) In the given problem, one parent has genotype AabbCcDdEeFf and other has genotype AABBCcDDEEff.

For gene A there will be cross of Aa X Aa. The probability of having heterozygous genotype Aa will be 2/4 =1/2

For gene B, there will be a cross of bb X BB. The probability of having heterozygous genotype Bb will be 4/4 =1

For gene C, there will be cross of Cc X Cc. The probability of having heterozygous genotype Cc will be 2/4 =1/2

For gene D, there will be cross of Dd X DD. The probability of having heterozygous genotype Dd will be 2/4 =1/2

For gene E, there will be cross of Ee X EE. The probability of having heterozygous genotype Ee will be 2/4 =1/2

For gene F, there will be cross of Ff X ff. The probability of having heterozygous genotype Ff will be 2/ =1/2

Hence the probability of offspring having all the heterozygous genes will be 1/2 *1 *1/2*1/2*1/2*1/2 =1/32