Question

# What percentage of the offspring will be heterozygous for all six genes? Aa bb Cc Dd...

What percentage of the offspring will be heterozygous for all six genes?

Aa bb Cc Dd Ee Ff x AA BB Cc DD EE ff

Ans :-) In the given problem, one parent has genotype AabbCcDdEeFf and other has genotype AABBCcDDEEff.

For gene A there will be cross of Aa X Aa. The probability of having heterozygous genotype Aa will be 2/4 =1/2

For gene B, there will be a cross of bb X BB. The probability of having heterozygous genotype Bb will be 4/4 =1

For gene C, there will be cross of Cc X Cc. The probability of having heterozygous genotype Cc will be 2/4 =1/2

For gene D, there will be cross of Dd X DD. The probability of having heterozygous genotype Dd will be 2/4 =1/2

For gene E, there will be cross of Ee X EE. The probability of having heterozygous genotype Ee will be 2/4 =1/2

For gene F, there will be cross of Ff X ff. The probability of having heterozygous genotype Ff will be 2/ =1/2

Hence the probability of offspring having all the heterozygous genes will be 1/2 *1 *1/2*1/2*1/2*1/2 =1/32

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