Consider a population having the following genotypes: Nn, Nn, NN, Nn, nn, Nn, NN, nn, Nn, nn.
Answer a :
There are 10 given individuals with three different
genotypes
There are 2 individuals with the genotype NN
Therefore frequency of genotype NN = 2/10 =
0.2
Answer b:
There are 10 individuals given. They have 2 alleles each.
Therefore there are a total of 20 alleles
The allele n is present 11 times in all the genotypes
(Heterozygous or homozygous)
Therefore frequency of allele n = 11/20 = 0.55
Answer c :
The genotype Nn has a dominant allele N and a recessive allele
n. Because N is dominant, the phenotype expressed by Nn will be
similar to the phenotype expressed by the individuals with
genotype NN.
The recessive allele is only expressed in genotypes where both the
alleles are recessive - nn
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