Question

PLEASE EXPLAIN YOUR ANSWER COMPLETLY AND CORRECTLY. THANK YOU!

Consider a yeast cell which wants to express a 900 bp gene. Assuming this gene has no introns, ignoring any 5’ or 3’ untranslated regions, and assuming a 100 bp poly-A tail, how many nucleotides are required to transcribe this gene? For simplicity’s sake, let’s assume all the nucleotides are ATP.

Based on what you know about translation, how many ATPs (or GTPs) would required to translate this protein?

Given the total number of ATPs required for transcription and translation, how many glucose molecules would be required to generate enough ATPs?

If the total amount of protein in the yeast cell is 10-20 mol, how much glucose is required to synthesize all the cellular protein (assume all proteins are identical to the one you’ve calculated in steps 1-3)?

Answer 1

Total 1000 nucleotide required to form mRNA

And total 300 amino acids are attached with peptide bond to form protein as 900 is region of gene and 100bp is length of poly A tail.

Total ATP required in mRNA synthsis is 1000x 3ATP= 3000ATP.

In one peptide bond formation 4 ATP required so total 900X 4= 3600 ATP required.

So total ATP require is 3600+3000= 6600ATP

In complete oxidation of one glucose release 36ATP.

So for 6600ATP we required 1/36X 6600= 184 glucose

In 20 mole of protein, amount of glucose will be 20X 184= 3680 glucose molecule

Hope it's clear..thanks