Question

Absorbance Values for BSA Standard Curve BSA Concentration (mg/mL) Absorbance Trial 1 Absorbance Trial 2 Absorbance...

Absorbance Values for BSA Standard Curve

BSA Concentration (mg/mL)

Absorbance Trial 1

Absorbance Trial 2

Absorbance Trial 3

Absorbance Trial 4

Absorbance Trial 5

Absorbance Trial 6

0.2

0.239

0.247

0.195

0.234

0.287

0.280

0.4

0.510

0.499

0.513

0.522

0.586

0.549

0.6

0.796

0.771

0.695

0.754

0.799

0.800

0.8

1.045

1.002

0.999

1.023

1.015

1.018

1.0

1.260

1.197

1.045

1.200

1.243

1.107

Absorbance Values for IgG Standard Curve

IgG Concentration (mg/mL)

Absorbance Trial 1

Absorbance Trial 2

Absorbance Trial 3

Absorbance Trial 4

Absorbance Trial 5

Absorbance Trial 6

0.2

0.135

0.122

0.105

0.117

0.142

0.118

0.4

0.317

0.300

0.335

0.314

0.323

0.295

0.6

0.502

0.488

0.485

0.472

0.503

0.402

0.8

0.668

0.650

0.677

0.701

0.690

0.628

1.0

0.865

0.806

0.824

0.914

0.853

0.822

Absorbance Values for BSA and IgG (0.5 mg/mL) Samples

Sample

Absorbance Trial 1

Absorbance Trial 2

Absorbance Trial 3

Absorbance Trial 4

Absorbance Trial 5

Absorbance Trial 6

BSA

(0.5 mg/mL)

0.624

0.652

0.602

0.620

0.621

0.630

IgG

(0.5 mg/mL)

0.394

0.390

0.395

0.382

0.385

0.374

Absorbance Values for Drink Samples

Sample

Absorbance Trial 1

Absorbance Trial 2

Absorbance Trial 3

Absorbance Trial 4

Absorbance Trial 5

Absorbance Trial 6

1

0.673

0.652

0.689

0.649

0.701

0.755

2

0.802

0.783

0.757

0.797

0.706

0.757

3

0.714

0.782

0.738

0.769

0.773

0.729

4

0.615

0.578

0.545

0.706

0.601

0.612

5

0.421

0.495

0.458

0.417

0.485

0.489

Information for Drink Samples

Sample

Description

Amount of Protein per serving size

Dilution Factor Used in Assay

1

Neilson 2% milk

9 g per 240 mL

50

2

So Nice Organic Almond

1 g per 250 mL

5

3

Natura Rice Organic Original

2 g per 250 mL

10

4

Organic Soy Milk

8 g per 250 mL

50

5

Boost Instant Breakfast

15 g per 280 mL

100

ONE figure of the standard curves. Both BSA and IgG curves should be presented in one graph. Only the standard curve absorbance values are to be plotted. The absorbance values associated with the BSA0.5 sample and beverage samples should not appear on your standard curves.

- Plot only the mean absorbance values. - Show the +/- y-axis standard deviation error bars.

- Even though this is a graph, it must be called a “Figure” in the title. The figure is numbered as well. - The title is placed underneath the graph

. (ii) ONE table listing the mean protein concentration (in mg/mL) and standard deviation for: - The 0.5 mg/mL BSA and IgG samples as calculated using the BSA standard curve - The 0.5 mg/mL BSA and IgG samples as calculated using the IgG standard curve - The table title should be placed above the table and is numbered.

(iii) ONE table listing the mean protein concentrations for each beverage sample as calculated from both BSA and the IgG standard curve slopes. Remember, each sample was assayed a total of six times. Don’t forget to include the dilution factor associated with each sample in your concentration calculations. An example table is provided below for you to follow. The required information for this table is: - The mean protein for each beverage sample (in mg/mL) calculated from the BSA slope and show the value converted to g/serving size as given by the manufacturer in mL - The mean protein for each beverage sample (in mg/mL) calculated from the IgG slope and show the value converted to g/serving size as given by the manufacturer in mL - Don’t forget to clearly indicate the names of the samples and the published protein content per serving and in mg/mL.

Homework Answers

Answer #1

Answer i. The mean and standard deviation of the absorbance value of the six trails for both BSA and IgG was computed. Fgiure (1) below shows the standard curve for both BSA and IgG (concentration versus absorbance). The points are the mean absorbnace values. The standard curves are almost linear and has postive trends. With increase in the concentration of the molecules, there is incresase in the absorbnace. BSA has comparative higher absorbnace than the IgG. The error bars shown in the figure is the standard deviation within the trials.

Know the answer?
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Not the answer you're looking for?
Ask your own homework help question
Similar Questions
STANDARD CURVE PREPARATION Always indicate the volume of water (or additional solution) to be added to...
STANDARD CURVE PREPARATION Always indicate the volume of water (or additional solution) to be added to complete any dilution. a) A stock solution of 6mg/ml BSA is provided. Calculate the dilutions for the preparation of the following BSA standards (2.0ml volumes of each): 60, 170, 500, 1500, 3000ug/ml. Also include the dilution factor for each preparation. On a separate sheet of paper with a heading of Calculations, include one complete sample calculation of this dilution calculation. b) To 0.5ml of...
if the slope of the calibration curve of absorbance vs concentration is 0.0681x+0 (mg/mL) how would...
if the slope of the calibration curve of absorbance vs concentration is 0.0681x+0 (mg/mL) how would I determine the concentration of a diluted solution (1/8 diluted with 0.424 absorbance)
You are performing a Bradford assay. You construct your standard curve (concentration in mg/mL on the...
You are performing a Bradford assay. You construct your standard curve (concentration in mg/mL on the x-axis, Absorbance on the y-axis) and derive a trendline with an equation of y = 0.25x (the intercept is set to zero because you blanked your spectrophotometer correctly). You dilute protein A using the volumes given below, to a final volume of 1000 μL, and measure the absorbance: 6 μL to 1000 μL = Abs 0.04 80 μL to 1000 μL = Abs 0.15...
The concentration of an undiluted sample is 26.4 mg/ml. To calculate that answer, the concentration of...
The concentration of an undiluted sample is 26.4 mg/ml. To calculate that answer, the concentration of the diluted sample was multiplied by the dilution factor. Knowing that the dilution factor is 2, work backwards to determine the concentration of the DILUTED sample. A. 13.2 mg/ml B. 132.0 mg/ml C. 1.32 mg/ml D. 26.4 mg/ml What is the unit used to describe cell solutions measured in a spectrophotometer? Cells/milliliter Grams (g) Optical density (OD) Meters (m) Spectroscopy is based on the...
Glucose (mg/mL) Absorbance (600 nm) 0.0 0.000 0.1 0.150 0.2 0.300 0.3 0.450 0.4 0.600 0.5...
Glucose (mg/mL) Absorbance (600 nm) 0.0 0.000 0.1 0.150 0.2 0.300 0.3 0.450 0.4 0.600 0.5 0.750 You are provided with a patient’s serum sample. In order to determine the glucose concentration in the serum sample you dilute it by adding 0.20 mL of the serum sample to 0.80 mL of saline.             Using the standard glucose assay, the absorbance reading for the diluted serum sample is 0.480.             Determine the glucose concentration in the patient’s serum sample.             State...
Fe 2+ Concentration Measured Absorbance 0.399 0.080 0.799 0.164 0.999 0.201 1.998 0.405 3.996 0.805 Using...
Fe 2+ Concentration Measured Absorbance 0.399 0.080 0.799 0.164 0.999 0.201 1.998 0.405 3.996 0.805 Using the above data for a standard curve, how can I determine the Concentration of iron (Fe+2) in Solution 3 and Solution 1? How can I also determine the average mass of iron in the tablet? C2(?) x V2(5.00mL) = C3(from standard curve) x V3(50.0 mL) C1(?) x V1 (5.00mL) = C2 x V2 (100.0 mL) Tablet Name:  ShopRite Iron (C)                   Mass (on label): 65 mg Trial...
Sample # 2.5 mM NPP (mL) NaCitrate buffer (mL) water (mL) 1 0.10 2 2.4 2...
Sample # 2.5 mM NPP (mL) NaCitrate buffer (mL) water (mL) 1 0.10 2 2.4 2 0.20 2 2.3 3 0.30 2 2.2 A) make a plot of Absorbance 405 nm vs time for each substrate concentration, displaying all 3 samples on the same plot. B) fit each data set to a trendline C) using the slopes from the trendlines in part B and the slope from your standard curve, convert your slopes into enzyme velocity values with units of...
Protein Assay Lab: the following are LDH Concentrations: LDH SAMPLE 1: 0.0065 mg/ml LDH SAMPLE 2:...
Protein Assay Lab: the following are LDH Concentrations: LDH SAMPLE 1: 0.0065 mg/ml LDH SAMPLE 2: 0.0135 mg/ml LDH SAMPLE 3: 0.0183 mg/ml LDH SAMPLE 4: 0.0271 mg/ml a) Do all of the values agree? b) what is the average c) what is the standard error
1. A standard solution of 100 ppm (100 mg / L) of an organic compound was...
1. A standard solution of 100 ppm (100 mg / L) of an organic compound was analyzed and this has a maximum absorption band at 270 nm. A calibration curve was prepared from which the following data were obtained: Conc. (Ppm) 1 1,5 2 3 4 Absorbance 0.1282   0.1940 0.2615 0.3995 0.5422        If 2 ml of an unknown solution of this compound are diluted to 50 ml, an absorbance of 0.425 is obtained. a. Calculate the concentration...
concentration HCl in mmol/mL= 0.403 concentration NaOH in mmol/mL= 0.11 Part IIC. Scoring Scheme: 3-3-2-1. Based...
concentration HCl in mmol/mL= 0.403 concentration NaOH in mmol/mL= 0.11 Part IIC. Scoring Scheme: 3-3-2-1. Based upon the molarities of the standardized HCl and standardized NaOH, and the volumes of each added to analyze the antacid samples, calculate the MILLIMOLES of HCl needed to neutralize the tablet per MILLIGRAM of sample. Use the same sequence as you entered the mass of the samples and report your results to 4 significant figures. Entry # mass tablet(g) mass antacid(g) Vol HCl(mL) Vol...
ADVERTISEMENT
Need Online Homework Help?

Get Answers For Free
Most questions answered within 1 hours.

Ask a Question
ADVERTISEMENT