A female mouse that is heterozygous for fur color where dark fur is dominant to light fur and homozygous dominant for long-tail length is mated with a male that is heterozygous for both traits. How many genotypes will be represented in the F1 generation?
A. |
4 |
|
B. |
6 |
|
C. |
8 |
|
D. |
12 |
|
E. |
16 |
ANSWER = 8
EXPLAINATION
SUPPOSE
colour gene is A and allele are A and a
Phenotype = Dark genotype= Aa or AA
Phenotype = light genotype = aa
Tail gene is L and alleles are L and l
Phenotype = long genotype = LL or Ll
Phenotype = tail genotype = ll
Female. x Male
Genotype. AaLL. AaLl
Phenotype. Dark fur long tail. Dark fur long tail
Gamete. AL , aL AL, Al , aL,al
MALE | |||||
GAMETES | AL | Al | aL | al | |
FEMALE | AL | AALL( DARK FURLONG) | AALl (DARK FUR LONG TAIL) | AaLL (DARK FUR LONG TAIL) | AaLl (DARK FUR LONG TAIL) |
aL | AaLL (DARK FUR LONG TAIL) | AaLl (DARK FUR LONG TAIL) | aaLL (LIGHT FUR LONG TAIL) | aaLl (LIGHT FUR LONG TAIL) |
TOTAL 8 GENOTYPE ( HIGHLETED IN TABLE)
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