Question

Q: The frequency of an allele in a population of manatees is 0.15. If the population is at Hardy-Weinberg, what number of the 600 individuals should be homozygous for this allele?

Please provide explanation

Answer 1

Answering this question by taking that the animal is in diploid condition.

Accoring to HW law (p+q)^2 = p^2+ 2pq+ q^2

p and q are the alleles.

p^2 - represents the p homozygous frequency
2pq - represents the heterozygote frequency
q^2 - represents the q homozygous frequency.

If the 0.15 is the frequency of q allele, the frequency of qq in the 600 population:

Step 1:
Findng the q^2 or qq genotype frequnecy = 0.15*0.15 = 0.0225

Step 2:
requency of qq in the 600 population: 0.0225 * 600 = 13.5 ~ 14.

So, the Answer is 14.