In fruit fly:
The w+ allele causes wild-type eye color, while the w allele causes a recessive white-eyed trait.
The y+ allele cause wild-type body color, while the y allele causes a recessive yellow-body trait.
The two parents in a cross are:
Parent 1: w+y+/w+y+
Parent 2: wy/wy
If their F1 progeny are crossed to wy/wy flies, then which of the following phenotypes among F2s must represent a recombinant?
Options:
A- white eyed and wild type body
B. white eyed and yellow body
C. wild type eyes and wild type body
A.white eyed and wild type body
Explanation-
cross between parents 1 and parents 2
parents 1 X parents 2
w+y+/w+y+ )(wild type eyed and wild type body) wy/wy (white eye and yellow body)
RESULTS
F1 generation = w+y+/wy(wild type eyed and wild type body)
As you know that if you cross between F1 generation and wy/wy then
Parental phenotype=(wild type eyed and wild type body) and white eye and yellow body)
And rest other phenotype in F2s will represent recombinant.
so, answer will be white eye and wild type body.
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