Question

What is normality of the concentrated reagent grade hydrochloric with density of 1.18 g/ml and purity of 38% ?

(2) Starting with this reagent grade hydrochloric acid, how would you prepare 100 ml of 1 N HCl ?

Answer 1

A)Normality = Molarity × Gram Equivalent

38% purity means there is 38g of solute per 100 g of solution.

Density is 1.18g/ml means 1180/L

To express the concentration in moles, we need molar mass of the acid which is 36.46.

Molarity = Purity × density × Mmolar

= 38/100 × 1180 × 1/36.46

= 12.2

Normality = Molarity × Gram equivalent

Gram equivalent of HCl is 1

= 12.2 × 1

= 12.2 N

B) Volume of HCl to be taken = (Molarity × Volume × Formula weight ) ÷ (Purity × Specific gravity)

= (1M × 0.1L × 36.46) × ((38/100) × 1.18)

= 3.646 × 0.44

= 1.63 ml

1.63 ml of HCl should be added to 100 ml of solvent.