A cladogram between four organisms is drawn based on similarity of rRNA. Which is most closely related?
P. aeruginosa - M. pneumoniae (52%); P. aeruginosa - C. botulinum (52%); P. aeruginosa - E. coli (79%); M. pneumoniae - C. botulinum (65%); M. pneumoniae - E. coli (52%); E. coli - C. botulinum (52%)
a |
M. pneumoniae - C. botulinum |
|
b |
E. coli - C. botulinum |
|
c |
P. aeruginosa - E. coli |
|
d |
P. aeruginosa - M. pneumoniae |
|
e |
P. aeruginosa - C. botulinum |
The determination of similarity on the basis of ribosomal RNA is being used to make phylogenetic relationships between the organisms. 16s rRNA similarity is one of its types. On its bases, when there is a greater percentage of similarity on the basis of rRNA, the organisms are considered to be closely related. Among the results given on the basis of rRNA similarity, P. aeruginosa and E. coli tend to have the highest similarity about 79%, which means they are the most closely related of them all.
Hence, the correct option is (c)
About the incorrect options-
All of the rest have less similarity of rRNA than the one mentioned in explanation. So, they are not closely related.
Hope it helps, Good luck !!!!
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